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Snark
Joined: 28 Dec 2006
Posts: 115
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 Posted: Tue Jun 12, 2007 8:41 pm Post subject: |
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| Quote: | | be VERY sure that the two leads from the battery will have no chance of coming into contact with each other, especially if things get moved around often (portable sensor bar).. |
Yes, this is true. I didn't mention it because I thought it was obvious, but I probably should have anyway. Thanks for pointing it out.  |
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CalcProgrammer1
Joined: 29 Jul 2007
Posts: 18
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| Posted: Sat Sep 01, 2007 6:55 pm Post subject: |
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| I tried building a sensor bar plug but I was using a piece of plastic and soldering metal plates to it, but I ended up melting the plastic and I couldn't get it to work. If I can find some rubber, this sounds like a good idea, maybe there's a way to build an outside shell to hold the plug in without tape. |
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abe
Joined: 12 Nov 2007
Posts: 5
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| Posted: Tue Nov 13, 2007 5:09 am Post subject: |
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| doesn't sound that easy |
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BuRN1N
Joined: 29 May 2008
Posts: 1
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| Posted: Thu May 29, 2008 5:21 am Post subject: 12v battery |
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| hey I do alarm systems and I was wondering, I have a boatload of 12v 4.5amp/h and 7amp/h is there any reason why this would be too much voltage? |
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Frivolous Sam
Joined: 18 May 2008
Posts: 16
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| Posted: Thu May 29, 2008 6:51 am Post subject: |
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| BuRN1N wrote: | | I have a boatload of 12v 4.5amp/h and 7amp/h is there any reason why this would be too much voltage |
Yes.
The Wii provides approximately 7.5V to the sensor bar. Powering it off 9V seems to work, but it is drawing too much current and the LEDs are having to dissipate that additional current as heat.
If you provide 12V then you will be drawing a larger current. You can see the circuit diagrams for the stock sensor bar in my diary thread.
Applying Ohm's law (V=IR), you can calculate that the 5 LEDs on each side would drop 1.25V each, totalling 6.25V. This leaves 5.75V over the 22 ohm current limiting resistor (on each side) making the current 261mA. This is a lot of current for the LEDs to dissipate! They might even go pop. the total current drawn would be over 0.5A and I'm not sure how well even the wire would cope with that.[/quote] |
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TiagoTiago
Joined: 20 Jan 2007
Posts: 710
Location: Brasil
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| Posted: Fri May 30, 2008 7:35 pm Post subject: |
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I think you would need to add more resistors (or perhaps another type of componen that will use up energy of the circuit, perhaps a bunch of power indicator leds, or a small fan (are there any that will not need too much energy and will not mess up the circuity in some other way?) or even some incadescent lightbulbs perhaps, dunno)
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please put the scripts on the wiki so they dont get lost as new stuff is posted!
phpBB doesnt like me,somtimes it will forget to warn me about new replies to threads I asked it to,if you see a thread I should have responded, could please email me? |
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